Pope Francis and Pope Benedict XVI both have Sower’s Sevens
in their documents.
Well, I am a bit miffed to find out that I am not the first
in today’s world to know about Sower’s Sevens.
When did the Vatican discover Sower’s Sevens? Certainly Pope Benedict’s use predates my
discovery of Sower’s Sevens. So we both discovered
this independently, or is the Vatican’s knowledge of Sower’s Sevens a tradition
passed along over the centuries from before the time of Jesus?
What are Sower’s Sevens?
That is my term for number patterns that exist in sacred texts, such as
the Bible which have hidden sevens. The
Sower’s Sevens (“70 x 7”) are released by simple arithmetic using the numbers in
the Sower’s parables in the Gospel, that is, 30 – 60 – 100 and 100 – 60 – 30. These numbers are like a key that unlock the
sevens.
I congratulate these popes for reproducing the biblical
number patterns in their papal documents.
While I know how to release the sevens, I’m not sure I would have the
patience to put sevens into a document.
Certainly the presence of “70 x 7” in the papal documents highlights
devotion to the Bible. However, doesn’t
it take a certain compulsiveness to be hiding sevens? Fortunately for the popes, there are people
like me willing to look for hidden sevens.
Otherwise, who would appreciate all their efforts?
Solution 1: Pope
Francis’ AMORIS LÆTITIA (On Love in the Family) March 19, 2016
It quickly became apparent to me that there might be hidden
sevens when I noticed that Francis’ book starts off with a block of 7 items and
the book concludes with a prayer with 7 paragraphs. Also the book has 9 chapters. A number divisible by 3 is a key to releasing
hidden sevens (9/3 = 3).
What sort of organization would encourage or require its
leaders to hide sevens in documents as what, a signature, a branding, a
watermark? Maybe just a way to honor
the authors of the Bible.
Here is a step by step description of how to release the “70
x 7” in Francis’ book:
The Index at the end of the book very helpfully lists the
chapters 1 – 9, and for each chapter the numbered items in it. For example, in chapter 1, there are items 8
– 30. Take the difference and you get 22
(30 minus 8 = 22). Do likewise for all
nine chapters.
Chapter-item values are arranged in three subsets as
follows, beginning with chapter 1, and each subset is summed:
Chapter 1, 8 through 30, difference is 22
Chapter 2, 31 through 57, difference is 26
Chapter 3, 58 through 88, difference is 30
Sum of values for chapters 1 – 3 = 78
Chapter 4, 89 through 164, difference is 75
Chapter 5, 165 through 198, difference is 33
Chapter 6, 199 through 258, difference is 59
Sum of values for chapters 4 – 6 = 167
Chapter 7, 259 through 290, difference is 31
Chapter 8, 291 through 312, difference is 21
Chapter 9, 313 through 325, difference is 12
Sum of values for chapters 7 – 9 = 64
Next I use the Sower’s numbers (100 – 60 – 30) and multiply
the first sum by 100, the second sum by 60, the third sum by 30:
100 x 78 = 7,800
60 x 167 = 10,020
30 x 64 = 1,920
Sum of products = 19,740, factor of 7
Next the reverse. I
use the Sower’s numbers 30 – 60 – 100:
30 x 78 = 2,340
60 x 167 = 10,020
100 x 64 = 6,400
Sum of products = 18,760, factor of 7
At this point I usually sum the sums of products. Since that didn’t work I took the difference,
in keeping with what seemed to be a theme of subtracting.
Subtracting 19,740 minus 18,760 = 980, factors of 2 x 70 x 7
The sheer beauty of this puzzle and sublime result amaze me. It is brilliant.
Solution 2: Pope
Benedict’s Compendium of the Catechism of the Catholic Church, June 28, 2005.
It quickly became apparent to me there might be Sower’s
Sevens when I noticed that Appendix B to the Catechism’s Compendium contained
12 items. Twelve is a special number in
the Bible and also divisible by 3 (12/3 = 4).
I noticed that the last item in the list was not something I recognized
as a “Formula of Catholic Doctrine.” A
bogus item, if such it is, may be a clue that there is a number set that was
rounded out.
You know, it is fine for us folks to say we can see the Sower’s
Sevens in the Bible, as most people these days know that the Bible is not
always literal, and it is not a shock to find out that numbers likely were
skewed to fit a pattern. But is a pope
allowed to reveal that he knows about Sower’s Sevens? Benedict reveals his knowing that the Bible
is not always literal, by putting such a puzzle into his Compendium (or maybe an
underling did it). Rather, popes are
supposed to say that the Bible is the word of God and that not a word of it is
suspect.
Interesting that Benedict’s Sower’s Sevens puzzle is first
rate as you would expect of an intellectual.
Notice that the sum of sums below equals 70, a special number in the
Bible. The trick is to take only the
chapter values and not verse values where there are citations.
Here is a step by step description of how to release the 70
x 7 in Benedict’s Compendium:
The values are arranged in their order in the document into
three subsets and each subset is summed:
2, 7 [7:12], 5 [5:3-12], 3
Sum = 17
4, 7, 12, 5
Sum = 28
7, 7, 7, 4
Sum = 25
Sum of sums = 70 !!!
Next I use the Sower’s numbers (100 – 60 – 30) and multiply
the first sum by 100, the second sum by 60, the third sum by 30:
100 x 17 = 1,700
60 x 28 = 1,680
30 x 25 = 750
Sum of products = 4,130, factor 70
Next the reverse. I
use the Sower’s numbers 30 – 60 – 100:
30 x 17 = 510
60 x 28 = 1,680
100 x 25 = 2,500
Sum of products = 4,690, factor of 70
Adding the sums of products:
4,130 + 4,690 = 8,820, factor of 18 x 70 x 7
This puzzle is easy to do yet sophisticated.
I am mostly grateful to organizations that purport to lead
people to a realization of spiritual truths, as long as they use persuasion and
not force, they do not proselytize to make themselves rich, and they realize
that despite great learning and great effort, they don’t know much more than
the rest of us.
Solution 3: The Kensington Rune Stone
I am adding the Kensington Rune Stone here because it reinforces
the idea that the Sower’s Sevens have been passed along through the
centuries. The Κoran brings us to the
seventh century CE. The Kensington Rune
Stone is dated 1362 CE.
This stone was found near Kensington, Minnesota in the US,
and indicates Viking visitors to Minnesota 130 years before Columbus journey to
the Americas. (Geologist Scott Wolter
says it is genuine and posits involvement of Templars per Amazon book page and
reviews for The Hooked X).
The stone has 12 lines (there’s that 12 again). It has 6 lines with numbers, with a total of
8 numbers. The solution is similar to
what I found for “Of Aseneth.” In that
text, uneven numbers of values centered on 3 dates. For the rune stone, the solution is to
combine, not the numbers, but rather, lines with their numbers, as follows.
Here are the 12 lines per wikipedia:
The text consists of 9 lines on the face of the stone, and 3
lines on the edge, read as follows:
Front:
Line 1> 8 :
göter : ok : 22 :
norrmen : po :
Line 2> ...o : opdagelsefärd : fro :
Line 3> vinland : of : vest : vi :
Line 4> hade : läger : ved : 2 : skjär : en :
Line 5> dags : rise : norr : fro :
deno : sten :
Line 6> vi : var : ok : fiske :
en : dagh : äptir :
Line 7> vi : kom : hem : fan : 10 : man : röde :
Line 8> af : blod : og : ded :
AVM :
Line 9> frälse : äf : illü.
Side:
Line 10> här : (10) :
mans : ve : havet : at : se :
Line 11> äptir : vore : skip : 14 : dagh : rise :
Line 12> from : deno : öh : ahr : 1362 :
The text describes a horrific attack, per wiki translation,
“Eight Geats and twenty-two Norwegians on
an exploration journey from Vinland to the west. We had camp by two skerries
one day's journey north from this stone. We were [out] to fish one day. After
we came home [we] found ten men red of blood and dead. AVM (Ave Virgen Maria)
save [us] from evil. [We] have ten men
by the sea to look after our ships, fourteen days' travel from this island. [In
the] year 1362.”
While Wikipedia is not reliable, I am going to accept it for
now per this rune.
Solution
Here is a step by step description of how I release the 70 x
7 on the rune stone.
Combine the values in Lines 1 and 4
8, 22, 2
Sum = 32
Combine the values in Lines 7 and 10
10, 10
Sum = 20
Combine the values in Lines 11 and 12
14, 13, 62*
Sum = 89
* The trick here is to take the year “1362” as two values,
13 and 62. I think this is justified as
“and” used to be inserted in dates – “in the year of Our Lord, thirteen hundred
and sixty-two” has a nice ring to it. I
don’t know if there is an “and” on the stone.
Next I use the Sower’s numbers (100 – 60 – 30) and multiply
the first sum by 100, the second sum by 60, the third sum by 30:
100 x 32 = 3,200
60 x 20 = 1,200
30 x 89 = 2,670
Sum of products = 7,070, factor 70
Well, when I saw that seven thousand and seventy,
I knew I was in the right neighborhood.
Next the reverse. I
use the Sower’s numbers 30 – 60 – 100:
30 x 32 = 960
60 x 20 = 1,200
100 x 89 = 8,900
Sum of products = 11,060, factor of 70
Sum of sum of products = 7,070 + 11,060 = 18,130, factor of 37
x 70 x 7
What would Viking Norsemen know of a tradition of Sower’s
Sevens found in the Bible, the Κoran, and in today’s Vatican documents? An online friend has told me that the Knights
Templar had dispersed due to attacks on them by the Vatican and thus could have
been among Vikings. I do recall that the
Templars had been crusaders in the Holy Land and thus maybe privy to its
secrets. There is mention of a Mary
Virgin on the stone.
With this solution, I have now completed 23 examples of
Sower’s Sevens. With all these examples
I believe I have a good feel for what is a good puzzle. This Kensington rune stone number puzzle is
perfection, even though I have a preference for subsets with an equal number of
values.
What are the odds?
What are the odds of getting a “70 x 7” as a factor? The odds are 1 in 490, but since I add a
factor of 10 in the process of doing the arithmetic, the odds are 1 in 49. What are the odds of getting a “70 x 7” in 23
examples? The odds are 1 in 7^23 (one in
seven to the 23rd power) – astronomical.
For sure I did not do enough sampling to beat the odds. The Sowers Sevens were embedded in the texts
by the writers.
Finding the difference between the sums of products will
always yield a 7-factor or zero, even when the sums of products themselves do
not contain a 7-factor; however, such difference will not necessarily contain a
7-squared-factor. Odds of obtaining such
randomly at this stage of the process is 1 in 7. Combined with 1 in 7 odds for a seven-factor
from the computation of the sums of products (assuming no more than two of the original
sums for a sum of products have 7-factors), the overall odds are 1 in 49.
Reviewing all of my previous 22 examples, I found none where
taking a difference between sums of products yielded a 70 x 7. So maybe Pope Francis (or his editor) has
taken a new approach in designing a Sower’s Sevens puzzle?
Can I say definitively that these popes, Francis and
Benedict, have imbedded sevens in their documents? I admit that I would like to have more
examples before coming to a conclusion.
However, I do feel fairly confident that there are Sower’s Sevens in the
documents, given that I have so many other examples from history and the
Vatican has been part of that history – so why wouldn’t they know the numerical
foundation of scriptures? Since I was
able to figure out that there are Sower’s Sevens in the Bible, I would hope
they have figured it out also after so many hundreds of years. I am at a loss however, to understand the
compulsion to put sevens in documents now in the 21st century.
Solution 4: Pope Francis LAUDATO SI’ (On Care For Our Common
Home) May 24, 2015
Well, I wrote all that and then decided to take a quick look
at Pope Francis’ environmental encyclical Laudato
Si. I’m not sure the following is a
solution that could have been what was intended, but it contains an interesting
twist.
The solution follows an algorithm similar to that for
Francis’ other book, Amoris Laetitia.
Step by step:
Laudato Si has 6 chapters.
For each of two chapters, take the difference in the number of
chapter-items.
Chapters 1, 2 = 100 – 17 = 83
Chapters 3, 4 = 162 – 101 = 61
Chapters 5, 6 = 245* – 163 = 82
* The trick here is
to not include the last item #246, that is after 5 stars and is a conclusion.
Multiply by 100 – 60 – 30 and then reverse
100 x 83 = 8,300
60 x 61 = 3660
30 x 82 = 2,460
Sum of products = 14,420, factor of 70
30 x 83 = 2,490
60 x 61 = 3,660
100 x 82 = 8,200
Sum of products = 14,350, factor of 70
Adding sums of products
14,420 + 14,350 = 28,770, factors 70 and 411
Where is the 70 x 7?
Breaking apart the 4-1-1, I get
100 x 4 = 400
60 x 1 = 60
30 x 1 = 30
Sum of products = 490 or 70 x 7
Reverse is:
30 x 4 = 120
60 x 1 = 60
100 x 1 = 100
Sum of products = 280 (factor of 70)
Sum of sum of products = 490 + 280 = 770 or seven
hundred seventy
What happens if I take the difference of the sums of
products above?
14,420 minus 14,350 = 70
I like this puzzle of the Pope’s and the ingenuity of it,
but I would rather have something more traditional. That was solution 24.
I feel fairly confident that I am working the numbers correctly
having eventually gotten “70 x 7” results using the same basic method
(chapter-items) on two of Francis’ books.
I don’t mean I am absolutely sure, as I can’t be sure there are even any
embedded sevens at all in Vatican documents.
Solution 5: another try at Francis’ Laudato Si
Can there be more than one solution to a Sower’s Sevens
puzzle? Yes, in fact the more
sophisticated a puzzle is, the more solutions, even within the same number set.
I went back to
Francis’ Laudato Si to see what else I could do with it.
Each of six chapters has Roman numeral headings within
it. Determine the total number of Roman
numerals per chapter. Arrange these
values in their order in the text in three subsets:
Chapters 1 and 2 = 14 Roman numerals
Chapters 3 and 4 = 7 Roman numerals
Chapters 5 and 6 = 14 Roman numerals
Sum = 35
This arrangement is very
unusual as all 3 values (14, 7, 14) are divisible by 7. Also the first and third subsets are equal.
Just look at all those 7 factors!
Multiplying by 100 – 60 – 30
100 x 14 = 1,400
60 x 7 = 420
30 x 14 = 420
Sum of products = 2,240
As expected, a factor of 70
Reverse
30 x 14 = 420
60 x 7 = 420
100 x 14 = 1,400
Sum of products = 2,240, factor of 70
As expected, identical to the previous sum of products.
I’ve never seen anything quite like this. Can it be biblical?
If I take the difference between the sums of products I get
zero. Sort of what you might expect for
an environmental encyclical on the end of the world.
If I add the sums of products do I get a “70 x 7”? No.
Adding the sums of products
2,240 + 2,240 = 4,480, factors of 2^7 and 35
Recall that there are 35 Roman numerals in this puzzle. So 35 appears again – a nice touch. If we sum the values in the 3 subsets for
both sums of products we get 70 (14
+ 7 + 14 + 14 + 7 + 14).
What about the 2^7?
That means 2 to the 7th power. Are
7 of 2 just as sacred as 2 of 7? Since I
have encountered this 2^7 as a solution for biblical puzzles before, I’ll say
yes.
Presumably, the Pope (or his editor) is putting in the
sevens-squared or the 2’s raised to the 7th power for an audience. Who is in this audience I don’t know. I doubt very much I am in the intended
audience, but nevertheless I appreciate and applaud. A lovely puzzle and I’m glad I spent the time
to find it and type it up. Of course, just
because I am finding puzzles and solutions doesn’t necessarily prove there
actually are such embedded.
Where to find 70 x 7 and 30-60-100 in the Bible:
Seven is a favored number in the Bible. The biblical “70
x 7” is found printed (not hidden) in Matthew 18:22 (footnote NRSV)
and also in Genesis 4:24. By the way, I believe that means seventy
times sevenfold (DRA), not 77 times.
The Sower’s Parables numbers can be found at: (1) Matthew
13:8 (100, 60, 30); (2) Matthew 13:23 (100, 60, 30); (3) Mark
4:8 (30, 60, 100); (4) Mark 4:20 (30, 60, 100); and (5) Luke 8:8
(100).
link to Pope
Francis’ Amoris Laetitia
link to Pope
Benedict’s Vatican Compendium in English
link to wiki Kensington Rune Stone
link to Francis’ Laudato Si
Update June 21, 2016
SOWER’S SEVENS IN FRANCIS’ LAUDATO SI AND AMORIS LÆTITIA
After taking a detour into the Temple of Solomon (side-bar)
where I was finally able to break the Temple codes in 1Kings and 2Chronicles, I
decided to make another try at Pope Francis’ Laudato Si and Amoris Laetitia.
Amazingly, both these documents issued by Pope Francis
employ a type of algorithm also present in the Temple of Solomon in 2Chronicles,
that is, assembling a number set by making a string of alternating even and odd
numbers. Both of Francis’ documents
share a sum of products (5,880) also present in 1Kings 7:23 (Solution 4 in
Temple of Solomon side-bar).
However, Pope Francis’ documents have the numbers embedded
in the formatting of the text, not in the text itself, as far as I know.
So with basically the same algorithm being used in both of
Pope Francis documents and finding the same sum of products, I am well prepared
to be convinced that I am onto something.
Does the Pope have time to play with numbers? I will make a guess that an editor was
assigned the task of making sure that whatever the Pope issues has been
properly filled with sacred numbers. To
what purpose? I don’t know. Maybe just to honor the biblical heritage of the
organization and especially to remember the Temple of Solomon, apparently built
to specifications that involved hidden sevens.
What does the Pope and his editor call these hidden sevens
that I call “Sower’s Sevens”? I don’t
know. I don’t think they are going to
tell me what they know. I sure hope they
have an app to help them embedding the sevens.
Solution 6: Another try at Pope Francis LAUDATO SI’ (On
Care For Our Common Home) May 24, 2015
The number set of 30 values is derived from the numbering of
the items in chapters and introduction.
To produce each value take the difference between the item number for
the last item and the first in that section.
Then create a string of 30 values by first taking an odd, then an even
number. (This is the reverse of
2Chronicles which is first even, then odd.)
Then put the 30 values in ascending order of 3 subsets of 10 values
each.
The trick is to count the zero differences as next even
numbers (if applicable) but not add them into a subset as they have no value. Is that kosher? Maybe yes if I get a good answer.
Step by step:
Here are the item differences with the 30 resultant odd and
even numbers bolded and underlined:
INTRO
2-1=1 heading ‘nothing’ 6-3=3 heading ‘united’ 9-7=2 heading ‘saint’ 12-10=2 heading ‘my’ 16-13=3
CHAPTER ONE
19-17=2 ROMAN NUMERAL I heading ‘pollution’ 22-20=2 heading ‘climate’
26-23=3 ROMAN NUMERAL
II 31-27=4 ROMAN NUMERAL III 42-32=10
ROMAN NUMERAL IV 47-43=4 ROMAN NUMERAL V 52-48=4
ROMAN NUMERAL VI 59-53=6 ROMAN NUMERAL VII 61-60=1
CHAPTER TWO
62=0 [even but no value]
ROMAN NUMERAL I 64-63= 1 ROMAN NUMERAL II 75-65=10 ROMAN NUMERAL III 83-76=7
ROMAN NUMERAL IV 88-84=4 ROMAN NUMERAL V 92-89=3 ROMAN NUMERAL VI 95-93=2 ROMAN NUMERAL VII 100-96=4
CHAPTER THREE
101=0 ROMAN NUMERAL
I 105-102=3 ROMAN NUMERAL II 114-106=8 ROMAN NUMERAL III 121-115=6
heading ‘practical’ 123-122=1 heading ‘the need’ 129-124=5
heading ‘new’ 136-130=6
CHAPTER FOUR
137=0 ROMAN NUMERAL
I 142-138=4 ROMAN NUMERAL II 146-143=3 ROMAN NUMERAL III 155-147=8 ROMAN NUMERAL IV 158-156=2
ROMAN NUMERAL V 162-159=3
CHAPTER FIVE
163=0 [even but no value]
ROMAN NUMERAL I 175-164=11 ROMAN NUMERAL II 181-176=5
ROMAN NUMERAL III 188-182=6 ROMAN NUMERAL IV 198-189=9 ROMAN NUMERAL V 201-199=2
CHAPTER SIX
202=0 ROMAN NUMERAL
I 208-203=5 ROMAN NUMERAL
II 215-209=6 ROMAN NUMERAL
III 221-216=5 ROMAN NUMERAL IV
227-222=5 ROMAN NUMERAL V 232-228=4 ROMAN NUMERAL VI 237-233=4
ROMAN NUMERAL VII 240-238=2 ROMAN NUMERAL VIII 242-241=1 ROMAN NUMERAL IX 245-243=2
ENDING
246=0
Put into ascending order and into 3 subsets of 10 values
each and sum:
1, 1, 1, 1, 1, 2, 2, 2, 2, 2
Sum = 15
3, 3, 3, 3, 3, 3, 4, 4, 4, 5
Sum = 35
5, 6, 6, 6, 7, 8, 8, 9, 10, 11
Sum = 76
Next multiply by Sower’s parables numbers 100-60-30:
100 x 15 = 1,500
60 x 35 = 2,100
30 x 76 = 2,280
Sum of products = 5,880, factors of 70 x 7 x 12
Thus a biblical 70 x 7 is achieved along with a factor of
12, a special number in the Bible.
Solution 7: Pope Francis’ AMORIS LÆTITIA (On Love
in the Family) March 19, 2016
The number set of 3 values is derived from the numbering of
the items in chapters and introduction.
To produce each value take the difference between the item number for
the last item and the first in that section.
Then create a string of 3 values by first taking an even, then an odd
number.
Chapter and introduction item values are arranged as
follows, beginning with the intro, then chapter 1 and so on. The first even value is bolded and
underlined. Likewise the first odd
value, and the next even value.
Introduction, 1 through 7, difference is 6
Chapter 1, 8 through 30, difference is 22
Chapter 2, 31 through 57, difference is 26
Chapter 3, 58 through 88, difference is 30
Chapter 4, 89 through 164, difference is 75
Chapter 5, 165 through 198, difference is 33
Chapter 6, 199 through 258, difference is 59
Chapter 7, 259 through 290, difference is 31
Chapter 8, 291 through 312, difference is 21
Chapter 9, 313 through 325, difference is 12
Next I use the Sower’s numbers (30-60-100) and multiply:
30 x 6 = 180
60 x 75 = 4,500
100 x 12 = 1,200
Sum of products = 5,880, factors of 70 x 7 x 12
Thus a biblical 70 x 7 is achieved along with a factor of
12, a special number in the Bible.
This is the same sum of products (5, 880) as for Solution 6
above and also in Solution 4 in the Temple of Solomon (side-bar).
This is a wonderful way for the Pope to honor biblical
traditions by mimicking the algorithms in 2Chronicles and 1Kings regarding the
Temple of Solomon !!!
The Temple of Solomon is an example of ecumenism as Solomon
called on a neighboring ruler to help him in constructing the Temple. So very refreshing that the Pope is
reflecting on the Temple of Solomon. Or
the Pope’s editor is doing this reflecting.
What are the odds?
I now have 29 examples of Sower’s Sevens in various religious
texts. What are the odds of getting a
“70 x 7” as a factor? The odds are 1 in
490, but since I add a factor of 10 in the process of doing the arithmetic, the
odds are 1 in 49. What are the odds of
getting a “70 x 7” in 29 examples? The
odds are 1 in 7^29 (one in seven to the 29th power) – astronomical.
Updated June 21, 2016
Posted June 18, 2016
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